## Complete Hand Example #11

Posted in Typical hands

Player A KГўв„ўВЈ, QГўв„ўВЈ, JГўв„ўВЈ, KГўв„ўВ , 10Гўв„ўВҐ, 9Гўв„ўВЈ, 6Гўв„ўВ¦, 5Гўв„ўВҐ, 3Гўв„ўВҐ, 3Гўв„ўВ , 2Гўв„ўВ¦
Player B 6Гўв„ўВЈ, 5Гўв„ўВЈ, 4Гўв„ўВЈ, 10Гўв„ўВ , 9Гўв„ўВ¦, 8Гўв„ўВ¦, 8Гўв„ўВ , 7Гўв„ўВ , 2Гўв„ўВЈ, AГўв„ўВ¦

Conditions: Knock card is the AГўв„ўВЈ, which means it is a must-gin hand. Player A has no count in any game. Player B has no count in the first game, a safe count of eight in the second game, and a safe count of 14 in the third game.

Play of the Hand:

Player A Гўв‚¬вЂњ Discards the KГўв„ўВ  as his safest card.

Player B Гўв‚¬вЂњ going to the deck, he pulls the 8Гўв„ўВҐ for six melded cards and throws the 10Гўв„ўВ , since his first consideration is to get under the two counts that are available to him.

Player A Гўв‚¬вЂњ Draws the QГўв„ўВ¦ from the deck and discards it as his safest card.

Player B Гўв‚¬вЂњ Obtains from the deck the QГўв„ўВҐ and discards it.

Player A Гўв‚¬вЂњ Picks the 9Гўв„ўВ  and discards the 10Гўв„ўВҐ.

Player B Гўв‚¬вЂњ Going to the deck, he obtains the JГўв„ўВ  and has a choice of discarding either it, which can be only used for Jacks, or the 9Гўв„ўВ¦ which can only be used for 9Гўв‚¬в„ўs. Since he holds the 8, and the QГўв„ўВ¦ was just discarded by his opponent, he throws the JГўв„ўВ  as the higher of the two cards.

Player A Гўв‚¬вЂњ Picks the JГўв„ўВҐ from the deck and discards it.

Player B Гўв‚¬вЂњ Obtains the 10Гўв„ўВЈ from the deck and has the choice of discarding it or the 9Гўв„ўВ¦. Although the 10Гўв„ўВҐ and the 10Гўв„ўВ  have been played and no 9Гўв‚¬в„ўs have been played, the 10Гўв„ўВЈ is at this point the more dangerous card since the KГўв„ўВ , QГўв„ўВҐ, JГўв„ўВ , JГўв„ўВҐ, 10Гўв„ўВҐ, and the 10Гўв„ўВ  have been played but none of the club suit has appeared. In addition, the entire club suit is open below the 10 and could tie up either the needed 8Гўв„ўВЈ or the 7Гўв„ўВЈ as well. Since the 9Гўв„ўВ¦ has no more value than the 10Гўв„ўВЈ did in getting under the count, the 9Гўв„ўВ¦ is discarded.

Player A Гўв‚¬вЂњ He takes the discard, which establishes his hand as 9Гўв‚¬в„ўs. In picking this card, he has committed himself to win rather than play to the wall even though he has no counts. His choice of discard at this point is limited to either the 2Гўв„ўВ¦ or the 6Гўв„ўВ¦. The 2Гўв„ўВ¦ could tie up the needed 3Гўв„ўВ¦ possibly, whereas the 6Гўв„ўВ¦ could not tie up any needed card. Therefore, he throws the 6Гўв„ўВ¦.

Player B Гўв‚¬вЂњ Draws the 7Гўв„ўВҐ from the deck and throws the 10Гўв„ўВЈ.

Player A Гўв‚¬вЂњ Takes the discard and throws the 2Гўв„ўВ¦. He has now a committed gin hand.

Player B Гўв‚¬вЂњ He must take the 2Гўв„ўВ¦, not just for its offensive possibility but because it can put him under the count of the last game by breaking his 7Гўв‚¬в„ўs. He discards the 7Гўв„ўВ .

Player A Гўв‚¬вЂњ Picks and throws the 10Гўв„ўВ¦.

Player B Гўв‚¬вЂњ Selects the AГўв„ўВҐ and discards the 7Гўв„ўВҐ. He is now under in two games. He will not in any circumstances go over the count of 8.

Player A Гўв‚¬вЂњ going to the deck, he pulls the AГўв„ўВЈ and since none of the cards that he holds are actually any safer, he throws the AГўв„ўВЈ.

Player B Гўв‚¬вЂњ Takes the discard and throws back the 2Гўв„ўВЈ, even though he has just picked the 2Гўв„ўВ¦. Although this move indicates that he is holding Aces, he is also forcing his opponent to hold a 3Гўв„ўВ¦, 4Гўв„ўВ¦, 5Гўв„ўВ¦ against his pick of the 2Гўв„ўВ¦.

Player A Гўв‚¬вЂњ Picks and throws the JГўв„ўВ¦.

Player B Гўв‚¬вЂњ Pulls the 4Гўв„ўВ  from the deck and now must throw the 2Гўв„ўВ¦ as the safest card. The 4Гўв„ўВ  still leaves him under in both games.

Player A Гўв‚¬вЂњ Draws the 8Гўв„ўВЈ from the deck. He is aware that no 8Гўв‚¬в„ўs have shown, nor have any of the clubs under the 8. He is further aware of the fact that, from his opponentГўв‚¬в„ўs throws, he is obviously under the count of 8. This means that his opponent either has nine melded, or, at worse, seven melded. If he has nine melded, the 8Гўв„ўВЈ would most likely gin him. If he has seven melded the 8Гўв„ўВЈ will not do any harm since his three-card combination must be 8 points or less. If he has seven melded, what could his three-card combination be? In view of the cards that have been played, he had picked an Ace which could give him a pair of Aces. Certainly it would not be with another 2 because he has just thrown back two Deuces. It could not be with a 3 because the two Deuces that were thrown were both under the two ThreeГўв‚¬в„ўs that the player is missing. So, if his opponent had either of the missing 3Гўв‚¬в„ўs, he would have had gin. The only other combination available would be the two missing Threes with a Deuce. However since both Deuces have been played from the two missing Threes, it is most unlikely that he would hold this combination. The percentages therefore favor the fact that he has nine melded. The 8Гўв„ўВЈ therefore cannot be thrown. What about the 5Гўв„ўВҐ? This appears to be a safe card, since his opponent cannot have three 5Гўв‚¬в„ўs if he gives him credit for the missing run. He cannot have the 6Гўв„ўВҐ, 7Гўв„ўВҐ, 8Гўв„ўВҐ since the 7Гўв„ўВҐ has been played and he would not be holding a combination that would keep him over the count. If he gives his opponent three 8Гўв‚¬в„ўs and 3 Aces, his missing run would have to be clubs between the 3 and 7. His likelihood of taking the hand to the wall is very slight since he is missing an Ace and either side of the lower club run. His only opportunity to win therefore is to throw his 5Гўв„ўВҐ and hope to buy a three. It is more unlikely at this point that his opponent has both missing Threes. He therefore throws the 5Гўв„ўВҐ.

Player B Гўв‚¬вЂњ Picks and throws the KГўв„ўВ¦.

Player A Гўв‚¬вЂњ Going to the deck, he buys the AГўв„ўВ , which he cannot throw for the reasons expressed on the last pick. He can still win his hand by breaking his 3Гўв‚¬в„ўs, which to him are definitely safe, and play for the single 2Гўв„ўВ . He discards the 3Гўв„ўВҐ.

Player B Гўв‚¬вЂњ Picks the 9Гўв„ўВҐ. Although he knows that his opponent is holding 9Гўв‚¬в„ўs, he is forced to throw it because of the count.

Player A Гўв‚¬вЂњ Counts the remaining cards in the deck and finds that there are 12 left. He then knows that he will not be giving up an extra pick to his opponent by picking this discard. The 9Гўв„ўВҐ is a most important pick to his hand in view of the fact that he is now holding two of his opponentГўв‚¬в„ўs most needed cards. If he were to buy another one, either the 3Гўв„ўВЈ, 4Гўв„ўВЈ, or 7Гўв„ўВЈ, he would then be unable to win his hand. By picking the 9Гўв„ўВҐ now and discarding the KГўв„ўВЈ, he is still in the same position to gin. However, he has the 8Гўв„ўВЈ tied up, so that if he were to pick the 3Гўв„ўВЈ, 4Гўв„ўВЈ, or 7Гўв„ўВЈ, he could then throw the QГўв„ўВЈ and still retain a possibility for gin. He then discards the KГўв„ўВЈ.

Player B Гўв‚¬вЂњ Draws the 2Гўв„ўВҐ from the deck, which he throws as a dead card.

Player A Гўв‚¬вЂњ Pulls from the deck the 3Гўв„ўВЈ and discards the QГўв„ўВЈ. Not only has he picked a possible gin card for his opponent, but he has also given himself one extra opportunity for gin with the established 3Гўв„ўВ¦.

Player B Гўв‚¬вЂњ Picks the 2Гўв„ўВ . He now has a choice of throwing either the 2 or the 4, neither of which is safe at this point or he also could attempt to take the hand to the wall. He knows from the plays just made that his opponent is sitting with seven melded. What are the missing three cards? They must obviously include one or two of his needed cards since he has seen his opponent break a possible gin combination. He knows that his opponent has the 8Гўв„ўВЈ tied up by his pick of the 9Гўв„ўВЈ and throw off from the top end of his club run. His opponent must be holding the AГўв„ўВ , since Aces are a definite known run. What could he be holding with it though is the question. Obviously he is holding the 3Гўв„ўВ , so that the 2 cannot be thrown. He could be holding the AГўв„ўВ , 3Гўв„ўВ , 5Гўв„ўВ  so that the 4Гўв„ўВ  is a gin possibility, or he could be holding one of the two missing 3Гўв‚¬в„ўs. Most likely it would be the 3Гўв„ўВЈ since he is missing all of the higher clubs. So, what are the chances of ginning him or of going to the wall? Actually they are 50/50. If he is holding the AГўв„ўВ , 3Гўв„ўВ , 5Гўв„ўВ , his hand is dead. If the dealer breaks his three Aces, which he can do and remain under the count, he has no problem in subsequent throws because he knows that the only way his opponent can gin now is with the remaining three, if this was his holding. If the dealer picks the three he will have the opponent dead and can throw anything, regardless of count. He also knows that if he decides to play for gin, his opponent must use the 2Гўв„ўВ , but does not necessarily have to use the 4Гўв„ўВ . Since he has a 50/50 chance of getting by with the 4Гўв„ўВ , the determining factor of whether to throw this card or play to the wall are the odds in his favor. If he gets away with the 4Гўв„ўВ  and gins his hand, he wins all three games, whereas if the 4Гўв„ўВ  turns out to gin his opponent, he only loses one game. He therefore takes advantage of the odds in his favor and throws the 4Гўв„ўВ .

Player A Гўв‚¬вЂњ Draws from the deck and gets a 5Гўв„ўВ¦. He discards it.

Player B Гўв‚¬вЂњ Picks the 5Гўв„ўВ  and discards it. He is now reasonably sure of his opponentГўв‚¬в„ўs holdings.

Player A Гўв‚¬вЂњ Draws the 7Гўв„ўВЈ from the deck. He now is in a perfect position. He knows his opponentГўв‚¬в„ўs holding and knows that he has him completely dead, whereas he has two ways to gin going for him. Since his opponent has nine melded he cannot be holding more than one of these two cards. He discards the JГўв„ўВЈ.

Player B Гўв‚¬вЂњ Going to the deck, he buys the QГўв„ўВ  and discards it.

Player A Гўв‚¬вЂњ Picks and discards the 7Гўв„ўВ¦.

Player B Гўв‚¬вЂњ On his last pick he obtains the 3Гўв„ўВ¦. Now knowing that he has his opponent completely dead, he discards the AГўв„ўВ¦. The hand is then over.

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